BALDOR
14x ²y ²-28x ³+56x4=14x ²(y ²-2x+4x ²)
34ax ²+51a ²y-68ay ²=17a(2x ²+3ay-4y ²)
96-48mn ²+144n ³=48(2-mn ²+3n ³)
a ²b ²c ²-a ²c ²x ²+a ²c ²y ²=a ²c ²(b ²-x ²+y ²)
55m ²n ³x+110m ²n ³x ²-220m ²y ³=55m ²(n ³x+2n ³x ²-4y ³)
DESCOMPOSICION EN DOS FACTORES:
(a+b-c)(x-3)-(b-c-a)(x-3)=
=(x-3) [ (a+b-c)-(b-c-a)] =(x-3)(a+b-c-b+c+a)
=(x-3)2a
3x(x-1)-2y(x-1)+z(x-1)=
=(x-1)(3x-2y+z)
a(n+1) -b(n+1)-n-1=
=a(n+1)-b(n+1)-1(n+1)=
=(n+1)(a-b-1)
X(a+2)-a-2+3(a+2)=
=x(a+2)-1(a+2)+3(a+2)=
(a+2)(x+2)
X(a+2)-a-2+3(a+2)=
=x(a+2)-1(a+2)+3(a+2)=
(a+2)(x+2)
(1+3a)(x+1)-2a(x+1)+3(x+1)=
=(x+1)(1+3a-2a+3)=
=(x+1)(a+4)
(3x+2)(x+y-z)-(3x+2)-(x+y-1)(3x+2)=
=(3x+2) [ (x+y-z)(-1)-(x+y-1) ]
=(3x+2)(-z)
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